Base | Representation |
---|---|
bin | 11000011001111001… |
… | …01000100000011001 |
3 | 1020211002221210221001 |
4 | 30030330220200121 |
5 | 203313120414113 |
6 | 10004035545001 |
7 | 642453131266 |
oct | 141474504031 |
9 | 36732853831 |
10 | 13102123033 |
11 | 5613896a5a |
12 | 2657a5b161 |
13 | 130a5a992c |
14 | 8c415026d |
15 | 51a3c57dd |
hex | 30cf28819 |
13102123033 has 4 divisors (see below), whose sum is σ = 13102418560. Its totient is φ = 13101827508.
The previous prime is 13102123009. The next prime is 13102123081. The reversal of 13102123033 is 33032120131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13102123033 - 221 = 13100025881 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13102123033.
It is not an unprimeable number, because it can be changed into a prime (13102123093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66285 + ... + 174922.
It is an arithmetic number, because the mean of its divisors is an integer number (3275604640).
Almost surely, 213102123033 is an apocalyptic number.
It is an amenable number.
13102123033 is a deficient number, since it is larger than the sum of its proper divisors (295527).
13102123033 is an equidigital number, since it uses as much as digits as its factorization.
13102123033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 295526.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 13102123033 its reverse (33032120131), we get a palindrome (46134243164).
The spelling of 13102123033 in words is "thirteen billion, one hundred two million, one hundred twenty-three thousand, thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.063 sec. • engine limits •