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131021310012300 = 2232521959891459163
BaseRepresentation
bin11101110010100111000110…
…101001000010101110001100
3122011220111220100222111112200
4131302213012221002232030
5114133123120330343200
61142354205304001500
736411656126445321
oct3562470651025614
9564814810874480
10131021310012300
1138824909868834
1212840983760290
13581534475a956
14244d672896b48
151023271a97800
hex7729c6a42b8c

131021310012300 has 432 divisors, whose sum is σ = 444560577552000. Its totient is φ = 32173471503360.

The previous prime is 131021310012287. The next prime is 131021310012371. The reversal of 131021310012300 is 3210013120131.

131021310012300 is a `hidden beast` number, since 1 + 31 + 0 + 21 + 310 + 0 + 1 + 2 + 300 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 89062519 + ... + 90521681.

It is an arithmetic number, because the mean of its divisors is an integer number (1029075411000).

Almost surely, 2131021310012300 is an apocalyptic number.

131021310012300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131021310012300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (222280288776000).

131021310012300 is an abundant number, since it is smaller than the sum of its proper divisors (313539267539700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131021310012300 is a wasteful number, since it uses less digits than its factorization.

131021310012300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1459350 (or 1459340 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 131021310012300 its reverse (3210013120131), we get a palindrome (134231323132431).

The spelling of 131021310012300 in words is "one hundred thirty-one trillion, twenty-one billion, three hundred ten million, twelve thousand, three hundred".