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131021310103 = 475867475147
BaseRepresentation
bin111101000000101111…
…0101000100010010111
3110112012002201011200221
41322001132220202113
54121312423410403
6140105041215211
712315554521555
oct1720136504227
9415162634627
10131021310103
1150625128572
1221486931507
13c480663538
1464acda2bd5
15361c853dbd
hex1e817a8897

131021310103 has 8 divisors (see below), whose sum is σ = 133832086272. Its totient is φ = 128211496056.

The previous prime is 131021310097. The next prime is 131021310137. The reversal of 131021310103 is 301013120131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131021310103 is a prime.

It is a super-2 number, since 2×1310213101032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131021310143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38176 + ... + 513322.

It is an arithmetic number, because the mean of its divisors is an integer number (16729010784).

Almost surely, 2131021310103 is an apocalyptic number.

131021310103 is a deficient number, since it is larger than the sum of its proper divisors (2810776169).

131021310103 is an equidigital number, since it uses as much as digits as its factorization.

131021310103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 481061.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 131021310103 its reverse (301013120131), we get a palindrome (432034430234).

The spelling of 131021310103 in words is "one hundred thirty-one billion, twenty-one million, three hundred ten thousand, one hundred three".

Divisors: 1 47 5867 275749 475147 22331909 2787687449 131021310103