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1310214220001 is a prime number
BaseRepresentation
bin10011000100001110110…
…110100110100011100001
311122020220002012120221122
4103010032312212203201
5132431304320020001
62441523141502025
7163442221054421
oct23041666464341
94566802176848
101310214220001
11465727851925
12191b18111915
13967252aa4bb
14475b3d52481
15241359eab1b
hex1310eda68e1

1310214220001 has 2 divisors, whose sum is σ = 1310214220002. Its totient is φ = 1310214220000.

The previous prime is 1310214219961. The next prime is 1310214220013. The reversal of 1310214220001 is 1000224120131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1277914941601 + 32299278400 = 1130449^2 + 179720^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310214220001 - 226 = 1310147111137 is a prime.

It is a super-2 number, since 2×13102142200012 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1310214226001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655107110000 + 655107110001.

It is an arithmetic number, because the mean of its divisors is an integer number (655107110001).

Almost surely, 21310214220001 is an apocalyptic number.

It is an amenable number.

1310214220001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310214220001 is an equidigital number, since it uses as much as digits as its factorization.

1310214220001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1310214220001 its reverse (1000224120131), we get a palindrome (2310438340132).

The spelling of 1310214220001 in words is "one trillion, three hundred ten billion, two hundred fourteen million, two hundred twenty thousand, one".