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1310214223741 is a prime number
BaseRepresentation
bin10011000100001110110…
…110100111011101111101
311122020220002012210002011
4103010032312213131331
5132431304320124431
62441523141531221
7163442221101343
oct23041666473575
94566802183064
101310214223741
11465727854715
12191b18113b11
13967252ac107
14475b3d53993
15241359ebcb1
hex1310eda777d

1310214223741 has 2 divisors, whose sum is σ = 1310214223742. Its totient is φ = 1310214223740.

The previous prime is 1310214223733. The next prime is 1310214223753. The reversal of 1310214223741 is 1473224120131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1253750484100 + 56463739641 = 1119710^2 + 237621^2 .

It is an emirp because it is prime and its reverse (1473224120131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1310214223741 - 23 = 1310214223733 is a prime.

It is a super-2 number, since 2×13102142237412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310214223771) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655107111870 + 655107111871.

It is an arithmetic number, because the mean of its divisors is an integer number (655107111871).

Almost surely, 21310214223741 is an apocalyptic number.

It is an amenable number.

1310214223741 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310214223741 is an equidigital number, since it uses as much as digits as its factorization.

1310214223741 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 31.

Adding to 1310214223741 its reverse (1473224120131), we get a palindrome (2783438343872).

The spelling of 1310214223741 in words is "one trillion, three hundred ten billion, two hundred fourteen million, two hundred twenty-three thousand, seven hundred forty-one".