131021434110340 has 96 divisors (see below), whose sum is σ = 285896873203200. Its totient is φ = 50394401418240.

The previous prime is 131021434110313. The next prime is 131021434110349. The reversal of 131021434110340 is 43011434120131.

It is a super-4 number, since 4×131021434110340⁴ (a number of 58 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131021434110299 and 131021434110308.

It is not an unprimeable number, because it can be changed into a prime (131021434110349) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 133800705 + ... + 134776375.

It is an arithmetic number, because the mean of its divisors is an integer number (2978092429200).

Almost surely, 2^{131021434110340} is an apocalyptic number.

131021434110340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131021434110340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (142948436601600).

131021434110340 is an abundant number, since it is smaller than the sum of its proper divisors (154875439092860).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131021434110340 is a wasteful number, since it uses less digits than its factorization.

131021434110340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 977845 (or 977843 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 131021434110340 its reverse (43011434120131), we get a palindrome (174032868230471).

The spelling of 131021434110340 in words is "one hundred thirty-one trillion, twenty-one billion, four hundred thirty-four million, one hundred ten thousand, three hundred forty".