Base | Representation |
---|---|
bin | 11101110010100111001110… |
… | …101001101100101111000101 |
3 | 122011220112020201212012201022 |
4 | 131302213032221230233011 |
5 | 114133123404231331432 |
6 | 1142354230504240525 |
7 | 36411662350651343 |
oct | 3562471651545705 |
9 | 564815221765638 |
10 | 131021444402117 |
11 | 388249787088a5 |
12 | 12840a00770145 |
13 | 5815366552559 |
14 | 244d68667a993 |
15 | 102327d791b12 |
hex | 7729cea6cbc5 |
131021444402117 has 2 divisors, whose sum is σ = 131021444402118. Its totient is φ = 131021444402116.
The previous prime is 131021444402053. The next prime is 131021444402159. The reversal of 131021444402117 is 711204444120131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129101997637636 + 1919446764481 = 11362306^2 + 1385441^2 .
It is a cyclic number.
It is not a de Polignac number, because 131021444402117 - 26 = 131021444402053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131021444402417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510722201058 + 65510722201059.
It is an arithmetic number, because the mean of its divisors is an integer number (65510722201059).
Almost surely, 2131021444402117 is an apocalyptic number.
It is an amenable number.
131021444402117 is a deficient number, since it is larger than the sum of its proper divisors (1).
131021444402117 is an equidigital number, since it uses as much as digits as its factorization.
131021444402117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 35.
Adding to 131021444402117 its reverse (711204444120131), we get a palindrome (842225888522248).
The spelling of 131021444402117 in words is "one hundred thirty-one trillion, twenty-one billion, four hundred forty-four million, four hundred two thousand, one hundred seventeen".
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