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131021444431439 is a prime number
BaseRepresentation
bin11101110010100111001110…
…101001110011111001001111
3122011220112020201220200221022
4131302213032221303321033
5114133123404233301224
61142354230505024355
736411662351133002
oct3562471651637117
9564815221820838
10131021444431439
1138824978728931
1212840a007850bb
1358153665629c3
14244d686687539
15102327d79a65e
hex7729cea73e4f

131021444431439 has 2 divisors, whose sum is σ = 131021444431440. Its totient is φ = 131021444431438.

The previous prime is 131021444431333. The next prime is 131021444431463. The reversal of 131021444431439 is 934134444120131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131021444431439 - 212 = 131021444427343 is a prime.

It is a super-2 number, since 2×1310214444314392 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131021444431439.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131021444431639) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510722215719 + 65510722215720.

It is an arithmetic number, because the mean of its divisors is an integer number (65510722215720).

Almost surely, 2131021444431439 is an apocalyptic number.

131021444431439 is a deficient number, since it is larger than the sum of its proper divisors (1).

131021444431439 is an equidigital number, since it uses as much as digits as its factorization.

131021444431439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 497664, while the sum is 44.

The spelling of 131021444431439 in words is "one hundred thirty-one trillion, twenty-one billion, four hundred forty-four million, four hundred thirty-one thousand, four hundred thirty-nine".