Search a number
-
+
13102200233 = 43304702331
BaseRepresentation
bin11000011001111001…
…11011010110101001
31020211010002201211022
430030330323112221
5203313130401413
610004041342225
7642453602333
oct141474732651
936733081738
1013102200233
115613939a61
122657a97975
13130a605b05
148c4170453
1551a3dd608
hex30cf3b5a9

13102200233 has 4 divisors (see below), whose sum is σ = 13406902608. Its totient is φ = 12797497860.

The previous prime is 13102200211. The next prime is 13102200239. The reversal of 13102200233 is 33200220131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13102200233 - 28 = 13102199977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13102200239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152351123 + ... + 152351208.

It is an arithmetic number, because the mean of its divisors is an integer number (3351725652).

Almost surely, 213102200233 is an apocalyptic number.

It is an amenable number.

13102200233 is a deficient number, since it is larger than the sum of its proper divisors (304702375).

13102200233 is an equidigital number, since it uses as much as digits as its factorization.

13102200233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 304702374.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 13102200233 its reverse (33200220131), we get a palindrome (46302420364).

The spelling of 13102200233 in words is "thirteen billion, one hundred two million, two hundred thousand, two hundred thirty-three".

Divisors: 1 43 304702331 13102200233