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13102202230331 is a prime number
BaseRepresentation
bin1011111010101001100000…
…0111000001011000111011
31201101120002000000202121112
42332222120013001120323
53204131302232332311
643511022453030535
72521413533255444
oct276523007013073
951346060022545
1013102202230331
1141a1681649065
12157736502544b
137406bc7ca716
143342157442cb
1517ac41dce28b
hexbea981c163b

13102202230331 has 2 divisors, whose sum is σ = 13102202230332. Its totient is φ = 13102202230330.

The previous prime is 13102202230291. The next prime is 13102202230379. The reversal of 13102202230331 is 13303220220131.

13102202230331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13102202230331 is a prime.

It is a super-2 number, since 2×131022022303312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13102202230297 and 13102202230306.

It is not a weakly prime, because it can be changed into another prime (13102202230631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551101115165 + 6551101115166.

It is an arithmetic number, because the mean of its divisors is an integer number (6551101115166).

Almost surely, 213102202230331 is an apocalyptic number.

13102202230331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102202230331 is an equidigital number, since it uses as much as digits as its factorization.

13102202230331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13102202230331 its reverse (13303220220131), we get a palindrome (26405422450462).

The spelling of 13102202230331 in words is "thirteen trillion, one hundred two billion, two hundred two million, two hundred thirty thousand, three hundred thirty-one".