Base | Representation |
---|---|
bin | 10011000100001111010… |
… | …000101000100110011011 |
3 | 11122020220120001021212220 |
4 | 103010033100220212123 |
5 | 132431313041402443 |
6 | 2441523544035123 |
7 | 163442333056005 |
oct | 23041720504633 |
9 | 4566816037786 |
10 | 1310221044123 |
11 | 4657306929a2 |
12 | 191b1a462aa3 |
13 | 96726829644 |
14 | 475b4c0b375 |
15 | 241363e7a83 |
hex | 1310f42899b |
1310221044123 has 4 divisors (see below), whose sum is σ = 1746961392168. Its totient is φ = 873480696080.
The previous prime is 1310221043959. The next prime is 1310221044199. The reversal of 1310221044123 is 3214401220131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1310221044123 - 210 = 1310221043099 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1310221044093 and 1310221044102.
It is not an unprimeable number, because it can be changed into a prime (1310221044523) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218370174018 + ... + 218370174023.
It is an arithmetic number, because the mean of its divisors is an integer number (436740348042).
Almost surely, 21310221044123 is an apocalyptic number.
1310221044123 is a deficient number, since it is larger than the sum of its proper divisors (436740348045).
1310221044123 is an equidigital number, since it uses as much as digits as its factorization.
1310221044123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 436740348044.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 1310221044123 its reverse (3214401220131), we get a palindrome (4524622264254).
The spelling of 1310221044123 in words is "one trillion, three hundred ten billion, two hundred twenty-one million, forty-four thousand, one hundred twenty-three".
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