Base | Representation |
---|---|
bin | 111101000000110001… |
… | …0000010110001110001 |
3 | 110112012011101120220212 |
4 | 1322001202002301301 |
5 | 4121313141012032 |
6 | 140105112313505 |
7 | 12315565233665 |
oct | 1720142026161 |
9 | 415164346825 |
10 | 131022204017 |
11 | 50625689141 |
12 | 214870a2895 |
13 | c4808b7393 |
14 | 64ad1568a5 |
15 | 361c97dbb2 |
hex | 1e81882c71 |
131022204017 has 2 divisors, whose sum is σ = 131022204018. Its totient is φ = 131022204016.
The previous prime is 131022203989. The next prime is 131022204059. The reversal of 131022204017 is 710402220131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125233885456 + 5788318561 = 353884^2 + 76081^2 .
It is an emirp because it is prime and its reverse (710402220131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131022204017 - 222 = 131018009713 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131022203983 and 131022204001.
It is not a weakly prime, because it can be changed into another prime (131022204067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511102008 + 65511102009.
It is an arithmetic number, because the mean of its divisors is an integer number (65511102009).
Almost surely, 2131022204017 is an apocalyptic number.
It is an amenable number.
131022204017 is a deficient number, since it is larger than the sum of its proper divisors (1).
131022204017 is an equidigital number, since it uses as much as digits as its factorization.
131022204017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 672, while the sum is 23.
Adding to 131022204017 its reverse (710402220131), we get a palindrome (841424424148).
The spelling of 131022204017 in words is "one hundred thirty-one billion, twenty-two million, two hundred four thousand, seventeen".
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