Base | Representation |
---|---|
bin | 1011111010101001100101… |
… | …0010111011111111001111 |
3 | 1201101120010101110211101221 |
4 | 2332222121102323333033 |
5 | 3204131322331144101 |
6 | 43511024443344211 |
7 | 2521414164362356 |
oct | 276523122737717 |
9 | 51346111424357 |
10 | 13102222131151 |
11 | 41a169190091a |
12 | 157736b822067 |
13 | 7406c397795a |
14 | 33421824499d |
15 | 17ac43a10aa1 |
hex | bea994bbfcf |
13102222131151 has 2 divisors, whose sum is σ = 13102222131152. Its totient is φ = 13102222131150.
The previous prime is 13102222131007. The next prime is 13102222131179. The reversal of 13102222131151 is 15113122220131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13102222131151 - 219 = 13102221606863 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13102222131191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551111065575 + 6551111065576.
It is an arithmetic number, because the mean of its divisors is an integer number (6551111065576).
Almost surely, 213102222131151 is an apocalyptic number.
13102222131151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102222131151 is an equidigital number, since it uses as much as digits as its factorization.
13102222131151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 13102222131151 its reverse (15113122220131), we get a palindrome (28215344351282).
The spelling of 13102222131151 in words is "thirteen trillion, one hundred two billion, two hundred twenty-two million, one hundred thirty-one thousand, one hundred fifty-one".
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