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1310225557 is a prime number
BaseRepresentation
bin100111000011000…
…0111010010010101
310101022102100120111
41032012013102111
510140404204212
6334002403021
744316506404
oct11606072225
93338370514
101310225557
11612651943
12306960471
1317b5a83c4
14c602363b
157a05eea7
hex4e187495

1310225557 has 2 divisors, whose sum is σ = 1310225558. Its totient is φ = 1310225556.

The previous prime is 1310225519. The next prime is 1310225591. The reversal of 1310225557 is 7555220131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 818760996 + 491464561 = 28614^2 + 22169^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310225557 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1710225557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655112778 + 655112779.

It is an arithmetic number, because the mean of its divisors is an integer number (655112779).

Almost surely, 21310225557 is an apocalyptic number.

It is an amenable number.

1310225557 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310225557 is an equidigital number, since it uses as much as digits as its factorization.

1310225557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10500, while the sum is 31.

The square root of 1310225557 is about 36197.0379589270. The cubic root of 1310225557 is about 1094.2469769712.

Adding to 1310225557 its reverse (7555220131), we get a palindrome (8865445688).

The spelling of 1310225557 in words is "one billion, three hundred ten million, two hundred twenty-five thousand, five hundred fifty-seven".