Base | Representation |
---|---|
bin | 111101000000110010… |
… | …1000111100011100111 |
3 | 110112012012220112112221 |
4 | 1322001211013203213 |
5 | 4121313342310043 |
6 | 140105141453211 |
7 | 12315605131603 |
oct | 1720145074347 |
9 | 415165815487 |
10 | 131023010023 |
11 | 50626089764 |
12 | 21487411207 |
13 | c480b0a1c9 |
14 | 64ad2c6503 |
15 | 361ca8c8ed |
hex | 1e819478e7 |
131023010023 has 2 divisors, whose sum is σ = 131023010024. Its totient is φ = 131023010022.
The previous prime is 131023009987. The next prime is 131023010033. The reversal of 131023010023 is 320010320131.
It is a strong prime.
It is an emirp because it is prime and its reverse (320010320131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131023010023 - 213 = 131023001831 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131023009979 and 131023010006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131023010033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511505011 + 65511505012.
It is an arithmetic number, because the mean of its divisors is an integer number (65511505012).
Almost surely, 2131023010023 is an apocalyptic number.
131023010023 is a deficient number, since it is larger than the sum of its proper divisors (1).
131023010023 is an equidigital number, since it uses as much as digits as its factorization.
131023010023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 131023010023 its reverse (320010320131), we get a palindrome (451033330154).
The spelling of 131023010023 in words is "one hundred thirty-one billion, twenty-three million, ten thousand, twenty-three".
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