Base | Representation |
---|---|
bin | 11101110010101000101100… |
… | …101001001111010111010111 |
3 | 122011220200022122010221222111 |
4 | 131302220230221033113113 |
5 | 114133140121430340434 |
6 | 1142355051155411451 |
7 | 36412046416500256 |
oct | 3562505451172727 |
9 | 564820278127874 |
10 | 131023021340119 |
11 | 38825607868747 |
12 | 128411808b3b87 |
13 | 581555817226c |
14 | 244d795c8a79d |
15 | 1023321e37964 |
hex | 772a2ca4f5d7 |
131023021340119 has 2 divisors, whose sum is σ = 131023021340120. Its totient is φ = 131023021340118.
The previous prime is 131023021340059. The next prime is 131023021340203. The reversal of 131023021340119 is 911043120320131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131023021340119 - 213 = 131023021331927 is a prime.
It is a super-2 number, since 2×1310230213401192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131023081340119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511510670059 + 65511510670060.
It is an arithmetic number, because the mean of its divisors is an integer number (65511510670060).
Almost surely, 2131023021340119 is an apocalyptic number.
131023021340119 is a deficient number, since it is larger than the sum of its proper divisors (1).
131023021340119 is an equidigital number, since it uses as much as digits as its factorization.
131023021340119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 31.
The spelling of 131023021340119 in words is "one hundred thirty-one trillion, twenty-three billion, twenty-one million, three hundred forty thousand, one hundred nineteen".
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