Base | Representation |
---|---|
bin | 1011111010101001111000… |
… | …0100110011011001010011 |
3 | 1201101120022222100102212201 |
4 | 2332222132010303121103 |
5 | 3204132003342441034 |
6 | 43511040430104031 |
7 | 2521416160041004 |
oct | 276523604633123 |
9 | 51346288312781 |
10 | 13102302312019 |
11 | 41a17230959a8 |
12 | 157739264b017 |
13 | 74070746c45b |
14 | 334224b571ab |
15 | 17ac4aa9d014 |
hex | bea9e133653 |
13102302312019 has 2 divisors, whose sum is σ = 13102302312020. Its totient is φ = 13102302312018.
The previous prime is 13102302311977. The next prime is 13102302312023. The reversal of 13102302312019 is 91021320320131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13102302312019 - 215 = 13102302279251 is a prime.
It is a super-2 number, since 2×131023023120192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13102302312049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551151156009 + 6551151156010.
It is an arithmetic number, because the mean of its divisors is an integer number (6551151156010).
Almost surely, 213102302312019 is an apocalyptic number.
13102302312019 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102302312019 is an equidigital number, since it uses as much as digits as its factorization.
13102302312019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 28.
The spelling of 13102302312019 in words is "thirteen trillion, one hundred two billion, three hundred two million, three hundred twelve thousand, nineteen".
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