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13102302312023 is a prime number
BaseRepresentation
bin1011111010101001111000…
…0100110011011001010111
31201101120022222100102212212
42332222132010303121113
53204132003342441043
643511040430104035
72521416160041011
oct276523604633127
951346288312785
1013102302312023
1141a1723095a01
12157739264b01b
1374070746c462
14334224b571b1
1517ac4aa9d018
hexbea9e133657

13102302312023 has 2 divisors, whose sum is σ = 13102302312024. Its totient is φ = 13102302312022.

The previous prime is 13102302312019. The next prime is 13102302312049. The reversal of 13102302312023 is 32021320320131.

It is a weak prime.

It is an emirp because it is prime and its reverse (32021320320131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13102302312023 - 22 = 13102302312019 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13102302312023.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13102302312223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551151156011 + 6551151156012.

It is an arithmetic number, because the mean of its divisors is an integer number (6551151156012).

Almost surely, 213102302312023 is an apocalyptic number.

13102302312023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102302312023 is an equidigital number, since it uses as much as digits as its factorization.

13102302312023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13102302312023 its reverse (32021320320131), we get a palindrome (45123622632154).

The spelling of 13102302312023 in words is "thirteen trillion, one hundred two billion, three hundred two million, three hundred twelve thousand, twenty-three".