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131023121320153 is a prime number
BaseRepresentation
bin11101110010101000110010…
…100110101000100011011001
3122011220200120121021110210201
4131302220302212220203121
5114133140323024221103
61142355105130342201
736412052042350246
oct3562506246504331
9564820517243721
10131023121320153
1138825659246177
12128411aa28a961
135815572aa994a
14244d7a52745cd
15102332aad651d
hex772a329a88d9

131023121320153 has 2 divisors, whose sum is σ = 131023121320154. Its totient is φ = 131023121320152.

The previous prime is 131023121320141. The next prime is 131023121320241. The reversal of 131023121320153 is 351023121320131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125283517632144 + 5739603688009 = 11193012^2 + 2395747^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131023121320153 is a prime.

It is not a weakly prime, because it can be changed into another prime (131023121320253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511560660076 + 65511560660077.

It is an arithmetic number, because the mean of its divisors is an integer number (65511560660077).

Almost surely, 2131023121320153 is an apocalyptic number.

It is an amenable number.

131023121320153 is a deficient number, since it is larger than the sum of its proper divisors (1).

131023121320153 is an equidigital number, since it uses as much as digits as its factorization.

131023121320153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 28.

Adding to 131023121320153 its reverse (351023121320131), we get a palindrome (482046242640284).

The spelling of 131023121320153 in words is "one hundred thirty-one trillion, twenty-three billion, one hundred twenty-one million, three hundred twenty thousand, one hundred fifty-three".