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13102332111223 is a prime number
BaseRepresentation
bin1011111010101001111111…
…0110011110100101110111
31201101120102001102101200221
42332222133312132211313
53204132034010024343
643511043412515211
72521420001242105
oct276523766364567
951346361371627
1013102332111223
1141a1738999543
1215773a061bb07
137407106a3c14
14334228ab2c75
1517ac4d4d75ed
hexbea9fd9e977

13102332111223 has 2 divisors, whose sum is σ = 13102332111224. Its totient is φ = 13102332111222.

The previous prime is 13102332111217. The next prime is 13102332111257. The reversal of 13102332111223 is 32211123320131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13102332111223 - 25 = 13102332111191 is a prime.

It is a super-2 number, since 2×131023321112232 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13102332111023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551166055611 + 6551166055612.

It is an arithmetic number, because the mean of its divisors is an integer number (6551166055612).

Almost surely, 213102332111223 is an apocalyptic number.

13102332111223 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102332111223 is an equidigital number, since it uses as much as digits as its factorization.

13102332111223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13102332111223 its reverse (32211123320131), we get a palindrome (45313455431354).

The spelling of 13102332111223 in words is "thirteen trillion, one hundred two billion, three hundred thirty-two million, one hundred eleven thousand, two hundred twenty-three".