Base | Representation |
---|---|
bin | 1011111010101001111111… |
… | …0110011110100101110111 |
3 | 1201101120102001102101200221 |
4 | 2332222133312132211313 |
5 | 3204132034010024343 |
6 | 43511043412515211 |
7 | 2521420001242105 |
oct | 276523766364567 |
9 | 51346361371627 |
10 | 13102332111223 |
11 | 41a1738999543 |
12 | 15773a061bb07 |
13 | 7407106a3c14 |
14 | 334228ab2c75 |
15 | 17ac4d4d75ed |
hex | bea9fd9e977 |
13102332111223 has 2 divisors, whose sum is σ = 13102332111224. Its totient is φ = 13102332111222.
The previous prime is 13102332111217. The next prime is 13102332111257. The reversal of 13102332111223 is 32211123320131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13102332111223 - 25 = 13102332111191 is a prime.
It is a super-2 number, since 2×131023321112232 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13102332111023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551166055611 + 6551166055612.
It is an arithmetic number, because the mean of its divisors is an integer number (6551166055612).
Almost surely, 213102332111223 is an apocalyptic number.
13102332111223 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102332111223 is an equidigital number, since it uses as much as digits as its factorization.
13102332111223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13102332111223 its reverse (32211123320131), we get a palindrome (45313455431354).
The spelling of 13102332111223 in words is "thirteen trillion, one hundred two billion, three hundred thirty-two million, one hundred eleven thousand, two hundred twenty-three".
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