Base | Representation |
---|---|
bin | 111101000000110011… |
… | …0010100010101000011 |
3 | 110112012020111111220121 |
4 | 1322001212110111003 |
5 | 4121313432340413 |
6 | 140105152321111 |
7 | 12315610611442 |
oct | 1720146242503 |
9 | 415166444817 |
10 | 131023324483 |
11 | 50626283a47 |
12 | 21487543197 |
13 | c480bba38c |
14 | 64ad368d59 |
15 | 361cb00b8d |
hex | 1e81994543 |
131023324483 has 2 divisors, whose sum is σ = 131023324484. Its totient is φ = 131023324482.
The previous prime is 131023324423. The next prime is 131023324543. The reversal of 131023324483 is 384423320131.
It is a balanced prime because it is at equal distance from previous prime (131023324423) and next prime (131023324543).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131023324483 is a prime.
It is a super-2 number, since 2×1310233244832 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131023324403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511662241 + 65511662242.
It is an arithmetic number, because the mean of its divisors is an integer number (65511662242).
Almost surely, 2131023324483 is an apocalyptic number.
131023324483 is a deficient number, since it is larger than the sum of its proper divisors (1).
131023324483 is an equidigital number, since it uses as much as digits as its factorization.
131023324483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
The spelling of 131023324483 in words is "one hundred thirty-one billion, twenty-three million, three hundred twenty-four thousand, four hundred eighty-three".
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