Base | Representation |
---|---|
bin | 10011000100001111111… |
… | …111011001100101011111 |
3 | 11122020221102010010102212 |
4 | 103010033333121211133 |
5 | 132431324211202031 |
6 | 2441525102511035 |
7 | 163442542215215 |
oct | 23041777314537 |
9 | 4566842103385 |
10 | 1310233303391 |
11 | 4657375a6521 |
12 | 191b2259547b |
13 | 9672922c64c |
14 | 475b66bccb5 |
15 | 2413751a12b |
hex | 1310ffd995f |
1310233303391 has 2 divisors, whose sum is σ = 1310233303392. Its totient is φ = 1310233303390.
The previous prime is 1310233303367. The next prime is 1310233303429. The reversal of 1310233303391 is 1933033320131.
It is a weak prime.
It is an emirp because it is prime and its reverse (1933033320131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1310233303391 - 226 = 1310166194527 is a prime.
It is a super-2 number, since 2×13102333033912 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310233303091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655116651695 + 655116651696.
It is an arithmetic number, because the mean of its divisors is an integer number (655116651696).
Almost surely, 21310233303391 is an apocalyptic number.
1310233303391 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310233303391 is an equidigital number, since it uses as much as digits as its factorization.
1310233303391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13122, while the sum is 32.
The spelling of 1310233303391 in words is "one trillion, three hundred ten billion, two hundred thirty-three million, three hundred three thousand, three hundred ninety-one".
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