Base | Representation |
---|---|
bin | 10011000100010000011… |
… | …001011101011110010111 |
3 | 11122020221212222012201202 |
4 | 103010100121131132113 |
5 | 132431332433310223 |
6 | 2441525505143115 |
7 | 163442654250506 |
oct | 23042031353627 |
9 | 4566855865652 |
10 | 1310240135063 |
11 | 465740442232 |
12 | 191b2492aa9b |
13 | 9672a782062 |
14 | 475b757a83d |
15 | 24137e19428 |
hex | 1311065d797 |
1310240135063 has 2 divisors, whose sum is σ = 1310240135064. Its totient is φ = 1310240135062.
The previous prime is 1310240135011. The next prime is 1310240135111. The reversal of 1310240135063 is 3605310420131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1310240135063 - 28 = 1310240134807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310240135663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655120067531 + 655120067532.
It is an arithmetic number, because the mean of its divisors is an integer number (655120067532).
Almost surely, 21310240135063 is an apocalyptic number.
1310240135063 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310240135063 is an equidigital number, since it uses as much as digits as its factorization.
1310240135063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 1310240135063 its reverse (3605310420131), we get a palindrome (4915550555194).
The spelling of 1310240135063 in words is "one trillion, three hundred ten billion, two hundred forty million, one hundred thirty-five thousand, sixty-three".
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