Base | Representation |
---|---|
bin | 10011000100010000011… |
… | …100110011111011110101 |
3 | 11122020221221121211201012 |
4 | 103010100130303323311 |
5 | 132431333144412433 |
6 | 2441525540042005 |
7 | 163442664566516 |
oct | 23042034637365 |
9 | 4566857554635 |
10 | 1310241013493 |
11 | 465740992205 |
12 | 191b25093305 |
13 | 9672a9cbb39 |
14 | 475b7728a0d |
15 | 2413803e848 |
hex | 13110733ef5 |
1310241013493 has 2 divisors, whose sum is σ = 1310241013494. Its totient is φ = 1310241013492.
The previous prime is 1310241013457. The next prime is 1310241013559. The reversal of 1310241013493 is 3943101420131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1030190490289 + 280050523204 = 1014983^2 + 529198^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310241013493 is a prime.
It is a super-2 number, since 2×13102410134932 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310240013493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655120506746 + 655120506747.
It is an arithmetic number, because the mean of its divisors is an integer number (655120506747).
Almost surely, 21310241013493 is an apocalyptic number.
It is an amenable number.
1310241013493 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310241013493 is an equidigital number, since it uses as much as digits as its factorization.
1310241013493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 32.
The spelling of 1310241013493 in words is "one trillion, three hundred ten billion, two hundred forty-one million, thirteen thousand, four hundred ninety-three".
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