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1310241013493 is a prime number
BaseRepresentation
bin10011000100010000011…
…100110011111011110101
311122020221221121211201012
4103010100130303323311
5132431333144412433
62441525540042005
7163442664566516
oct23042034637365
94566857554635
101310241013493
11465740992205
12191b25093305
139672a9cbb39
14475b7728a0d
152413803e848
hex13110733ef5

1310241013493 has 2 divisors, whose sum is σ = 1310241013494. Its totient is φ = 1310241013492.

The previous prime is 1310241013457. The next prime is 1310241013559. The reversal of 1310241013493 is 3943101420131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1030190490289 + 280050523204 = 1014983^2 + 529198^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310241013493 is a prime.

It is a super-2 number, since 2×13102410134932 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310240013493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655120506746 + 655120506747.

It is an arithmetic number, because the mean of its divisors is an integer number (655120506747).

Almost surely, 21310241013493 is an apocalyptic number.

It is an amenable number.

1310241013493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310241013493 is an equidigital number, since it uses as much as digits as its factorization.

1310241013493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 32.

The spelling of 1310241013493 in words is "one trillion, three hundred ten billion, two hundred forty-one million, thirteen thousand, four hundred ninety-three".