Base | Representation |
---|---|
bin | 11101110010101001101101… |
… | …110001100100110110001100 |
3 | 122011220210010210021002022201 |
4 | 131302221231301210312030 |
5 | 114133144341143404200 |
6 | 1142355351432051244 |
7 | 36412115455355611 |
oct | 3562515561446614 |
9 | 564823123232281 |
10 | 131024114044300 |
11 | 3882601864a554 |
12 | 12841426833b24 |
13 | 58156a066a199 |
14 | 244d85b04a508 |
15 | 1023387d2bc6a |
hex | 772a6dc64d8c |
131024114044300 has 18 divisors (see below), whose sum is σ = 284322327476348. Its totient is φ = 52409645617680.
The previous prime is 131024114044259. The next prime is 131024114044303. The reversal of 131024114044300 is 3440411420131.
It is a super-2 number, since 2×1310241140443002 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131024114044303) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 655120570122 + ... + 655120570321.
Almost surely, 2131024114044300 is an apocalyptic number.
131024114044300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131024114044300 is an abundant number, since it is smaller than the sum of its proper divisors (153298213432048).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131024114044300 is a wasteful number, since it uses less digits than its factorization.
131024114044300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1310241140457 (or 1310241140450 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 131024114044300 its reverse (3440411420131), we get a palindrome (134464525464431).
The spelling of 131024114044300 in words is "one hundred thirty-one trillion, twenty-four billion, one hundred fourteen million, forty-four thousand, three hundred".
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