Base | Representation |
---|---|
bin | 10011000100010000100… |
… | …001000011000110100101 |
3 | 11122020222000201021022101 |
4 | 103010100201003012211 |
5 | 132431333440433242 |
6 | 2441530015532101 |
7 | 163443010203646 |
oct | 23042041030645 |
9 | 4566860637271 |
10 | 1310242124197 |
11 | 465741580746 |
12 | 191b2552a031 |
13 | 9672acca566 |
14 | 475b79376cd |
15 | 241381ad9b7 |
hex | 131108431a5 |
1310242124197 has 2 divisors, whose sum is σ = 1310242124198. Its totient is φ = 1310242124196.
The previous prime is 1310242124183. The next prime is 1310242124203. The reversal of 1310242124197 is 7914212420131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 967565355201 + 342676768996 = 983649^2 + 585386^2 .
It is an emirp because it is prime and its reverse (7914212420131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310242124197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310242124167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655121062098 + 655121062099.
It is an arithmetic number, because the mean of its divisors is an integer number (655121062099).
Almost surely, 21310242124197 is an apocalyptic number.
It is an amenable number.
1310242124197 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310242124197 is an equidigital number, since it uses as much as digits as its factorization.
1310242124197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 37.
The spelling of 1310242124197 in words is "one trillion, three hundred ten billion, two hundred forty-two million, one hundred twenty-four thousand, one hundred ninety-seven".
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