131024423041 has 4 divisors (see below), whose sum is σ = 131487407152. Its totient is φ = 130561438932.

The previous prime is 131024423029. The next prime is 131024423077. The reversal of 131024423041 is 140324420131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131024423041 - 2²³ = 131016034433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131024422997 and 131024423015.

It is not an unprimeable number, because it can be changed into a prime (131024423741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231491631 + ... + 231492196.

It is an arithmetic number, because the mean of its divisors is an integer number (32871851788).

Almost surely, 2^131024423041 is an apocalyptic number.

It is an amenable number.

131024423041 is a deficient number, since it is larger than the sum of its proper divisors (462984111).

131024423041 is an equidigital number, since it uses as much as digits as its factorization.

131024423041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 462984110.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 131024423041 its reverse (140324420131), we get a palindrome (271348843172).

The spelling of 131024423041 in words is "one hundred thirty-one billion, twenty-four million, four hundred twenty-three thousand, forty-one".