Base | Representation |
---|---|
bin | 111101000000110111… |
… | …0011001011010001111 |
3 | 110112012101111010012201 |
4 | 1322001232121122033 |
5 | 4121320003124242 |
6 | 140105305542331 |
7 | 12315634612324 |
oct | 1720156313217 |
9 | 415171433181 |
10 | 131025442447 |
11 | 506274a0229 |
12 | 214881a49a7 |
13 | c48147c403 |
14 | 64ad75ab4b |
15 | 361cdbd4b7 |
hex | 1e81b9968f |
131025442447 has 2 divisors, whose sum is σ = 131025442448. Its totient is φ = 131025442446.
The previous prime is 131025442393. The next prime is 131025442451. The reversal of 131025442447 is 744244520131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131025442447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131025442477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65512721223 + 65512721224.
It is an arithmetic number, because the mean of its divisors is an integer number (65512721224).
Almost surely, 2131025442447 is an apocalyptic number.
131025442447 is a deficient number, since it is larger than the sum of its proper divisors (1).
131025442447 is an equidigital number, since it uses as much as digits as its factorization.
131025442447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 107520, while the sum is 37.
Adding to 131025442447 its reverse (744244520131), we get a palindrome (875269962578).
The spelling of 131025442447 in words is "one hundred thirty-one billion, twenty-five million, four hundred forty-two thousand, four hundred forty-seven".
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