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131028113 is a prime number
BaseRepresentation
bin1111100111101…
…01010010010001
3100010112220210002
413303311102101
5232020344423
621000215345
73150502106
oct763652221
9303486702
10131028113
1167a643a7
1237a6a555
13211b8738
141358aaad
15b783228
hex7cf5491

131028113 has 2 divisors, whose sum is σ = 131028114. Its totient is φ = 131028112.

The previous prime is 131028097. The next prime is 131028127. The reversal of 131028113 is 311820131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129800449 + 1227664 = 11393^2 + 1108^2 .

It is a cyclic number.

It is not a de Polignac number, because 131028113 - 24 = 131028097 is a prime.

It is a plaindrome in base 14.

It is not a weakly prime, because it can be changed into another prime (131028173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65514056 + 65514057.

It is an arithmetic number, because the mean of its divisors is an integer number (65514057).

Almost surely, 2131028113 is an apocalyptic number.

It is an amenable number.

131028113 is a deficient number, since it is larger than the sum of its proper divisors (1).

131028113 is an equidigital number, since it uses as much as digits as its factorization.

131028113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

The square root of 131028113 is about 11446.7511984842. The cubic root of 131028113 is about 507.9116357453.

Adding to 131028113 its reverse (311820131), we get a palindrome (442848244).

The spelling of 131028113 in words is "one hundred thirty-one million, twenty-eight thousand, one hundred thirteen".