Base | Representation |
---|---|
bin | 111101000000111101… |
… | …1111010001100101111 |
3 | 110112012122011002011102 |
4 | 1322001323322030233 |
5 | 4121321410001443 |
6 | 140105513513315 |
7 | 12316006664345 |
oct | 1720173721457 |
9 | 415178132142 |
10 | 131028984623 |
11 | 5062949a549 |
12 | 2148941283b |
13 | c48211c784 |
14 | 64adddd995 |
15 | 361d36ccb8 |
hex | 1e81efa32f |
131028984623 has 2 divisors, whose sum is σ = 131028984624. Its totient is φ = 131028984622.
The previous prime is 131028984571. The next prime is 131028984637. The reversal of 131028984623 is 326489820131.
It is a strong prime.
It is an emirp because it is prime and its reverse (326489820131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131028984623 - 218 = 131028722479 is a prime.
It is a super-2 number, since 2×1310289846232 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131028984643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65514492311 + 65514492312.
It is an arithmetic number, because the mean of its divisors is an integer number (65514492312).
Almost surely, 2131028984623 is an apocalyptic number.
131028984623 is a deficient number, since it is larger than the sum of its proper divisors (1).
131028984623 is an equidigital number, since it uses as much as digits as its factorization.
131028984623 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 497664, while the sum is 47.
The spelling of 131028984623 in words is "one hundred thirty-one billion, twenty-eight million, nine hundred eighty-four thousand, six hundred twenty-three".
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