13103002117 has 2 divisors, whose sum is σ = 13103002118. Its totient is φ = 13103002116.

The previous prime is 13103002109. The next prime is 13103002151. The reversal of 13103002117 is 71120030131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12365662401 + 737339716 = 111201^2 + 27154^2 .

It is a cyclic number.

It is not a de Polignac number, because 13103002117 - 2³ = 13103002109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13103002094 and 13103002103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13103002817) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551501058 + 6551501059.

It is an arithmetic number, because the mean of its divisors is an integer number (6551501059).

Almost surely, 2^13103002117 is an apocalyptic number.

It is an amenable number.

13103002117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13103002117 is an equidigital number, since it uses as much as digits as its factorization.

13103002117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 126, while the sum is 19.

Adding to 13103002117 its reverse (71120030131), we get a palindrome (84223032248).

The spelling of 13103002117 in words is "thirteen billion, one hundred three million, two thousand, one hundred seventeen".