Base | Representation |
---|---|
bin | 11101110010101111100110… |
… | …001111111000011100010111 |
3 | 122011221101102222021011101221 |
4 | 131302233212033320130113 |
5 | 114133300310114101403 |
6 | 1142402314301431211 |
7 | 36412431132113266 |
oct | 3562574617703427 |
9 | 564841388234357 |
10 | 131030430222103 |
11 | 388287699a4405 |
12 | 128426a9b6b507 |
13 | 58161690a94b9 |
14 | 244dc99c405dd |
15 | 10236075bbdbd |
hex | 772be63f8717 |
131030430222103 has 2 divisors, whose sum is σ = 131030430222104. Its totient is φ = 131030430222102.
The previous prime is 131030430221947. The next prime is 131030430222227. The reversal of 131030430222103 is 301222034030131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131030430222103 - 241 = 128831406966551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131030430232103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515215111051 + 65515215111052.
It is an arithmetic number, because the mean of its divisors is an integer number (65515215111052).
Almost surely, 2131030430222103 is an apocalyptic number.
131030430222103 is a deficient number, since it is larger than the sum of its proper divisors (1).
131030430222103 is an equidigital number, since it uses as much as digits as its factorization.
131030430222103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 131030430222103 its reverse (301222034030131), we get a palindrome (432252464252234).
The spelling of 131030430222103 in words is "one hundred thirty-one trillion, thirty billion, four hundred thirty million, two hundred twenty-two thousand, one hundred three".
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