131030431443311 has 4 divisors (see below), whose sum is σ = 131030559031800. Its totient is φ = 131030303854824.

The previous prime is 131030431443283. The next prime is 131030431443319. The reversal of 131030431443311 is 113344134030131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131030431443311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131030431443319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62241176 + ... + 64311933.

It is an arithmetic number, because the mean of its divisors is an integer number (32757639757950).

Almost surely, 2^{131030431443311} is an apocalyptic number.

131030431443311 is a deficient number, since it is larger than the sum of its proper divisors (127588489).

131030431443311 is a wasteful number, since it uses less digits than its factorization.

131030431443311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127588488.

The product of its (nonzero) digits is 15552, while the sum is 32.

Adding to 131030431443311 its reverse (113344134030131), we get a palindrome (244374565473442).

The spelling of 131030431443311 in words is "one hundred thirty-one trillion, thirty billion, four hundred thirty-one million, four hundred forty-three thousand, three hundred eleven".