Base | Representation |
---|---|
bin | 11000011010000000… |
… | …01001011011110101 |
3 | 1020211011200121201120 |
4 | 30031000021123311 |
5 | 203313334404331 |
6 | 10004111414153 |
7 | 642464016312 |
oct | 141500113365 |
9 | 36734617646 |
10 | 13103044341 |
11 | 5614366172 |
12 | 2658224359 |
13 | 130a84009a |
14 | 8c430dd09 |
15 | 51a508796 |
hex | 30d0096f5 |
13103044341 has 4 divisors (see below), whose sum is σ = 17470725792. Its totient is φ = 8735362892.
The previous prime is 13103044333. The next prime is 13103044349. The reversal of 13103044341 is 14344030131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (13103044333) and next prime (13103044349).
It is a cyclic number.
It is not a de Polignac number, because 13103044341 - 23 = 13103044333 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13103044349) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183840721 + ... + 2183840726.
It is an arithmetic number, because the mean of its divisors is an integer number (4367681448).
Almost surely, 213103044341 is an apocalyptic number.
It is an amenable number.
13103044341 is a deficient number, since it is larger than the sum of its proper divisors (4367681451).
13103044341 is an equidigital number, since it uses as much as digits as its factorization.
13103044341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4367681450.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 13103044341 its reverse (14344030131), we get a palindrome (27447074472).
The spelling of 13103044341 in words is "thirteen billion, one hundred three million, forty-four thousand, three hundred forty-one".
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