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13103052517 = 19689634343
BaseRepresentation
bin11000011010000000…
…01011011011100101
31020211011201000221101
430031000023123211
5203313340140032
610004111520101
7642464052202
oct141500133345
936734630841
1013103052517
115614371325
122658229031
13130a843a19
148c4312ca9
1551a50ade7
hex30d00b6e5

13103052517 has 4 divisors (see below), whose sum is σ = 13792686880. Its totient is φ = 12413418156.

The previous prime is 13103052491. The next prime is 13103052539. The reversal of 13103052517 is 71525030131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 71525030131 = 254392811629.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13103052517 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13103052577) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 344817153 + ... + 344817190.

It is an arithmetic number, because the mean of its divisors is an integer number (3448171720).

Almost surely, 213103052517 is an apocalyptic number.

It is an amenable number.

13103052517 is a deficient number, since it is larger than the sum of its proper divisors (689634363).

13103052517 is an equidigital number, since it uses as much as digits as its factorization.

13103052517 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 689634362.

The product of its (nonzero) digits is 3150, while the sum is 28.

Adding to 13103052517 its reverse (71525030131), we get a palindrome (84628082648).

The spelling of 13103052517 in words is "thirteen billion, one hundred three million, fifty-two thousand, five hundred seventeen".

Divisors: 1 19 689634343 13103052517