Base | Representation |
---|---|
bin | 111101000001000001… |
… | …0101100001001000101 |
3 | 110112012202111101100011 |
4 | 1322002002230021011 |
5 | 4121322333341203 |
6 | 140110015550221 |
7 | 12316031046352 |
oct | 1720202541105 |
9 | 415182441304 |
10 | 131030762053 |
11 | 5062a4a39a4 |
12 | 21489b2b371 |
13 | c4825c27c9 |
14 | 64b0343629 |
15 | 361d5be76d |
hex | 1e820ac245 |
131030762053 has 2 divisors, whose sum is σ = 131030762054. Its totient is φ = 131030762052.
The previous prime is 131030762029. The next prime is 131030762059. The reversal of 131030762053 is 350267030131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101644917124 + 29385844929 = 318818^2 + 171423^2 .
It is a cyclic number.
It is not a de Polignac number, because 131030762053 - 29 = 131030761541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131030762059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515381026 + 65515381027.
It is an arithmetic number, because the mean of its divisors is an integer number (65515381027).
Almost surely, 2131030762053 is an apocalyptic number.
It is an amenable number.
131030762053 is a deficient number, since it is larger than the sum of its proper divisors (1).
131030762053 is an equidigital number, since it uses as much as digits as its factorization.
131030762053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340, while the sum is 31.
Adding to 131030762053 its reverse (350267030131), we get a palindrome (481297792184).
The spelling of 131030762053 in words is "one hundred thirty-one billion, thirty million, seven hundred sixty-two thousand, fifty-three".
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