Base | Representation |
---|---|
bin | 11101110010110000001001… |
… | …011111001101101110110111 |
3 | 122011221102222011202100102002 |
4 | 131302300021133031232313 |
5 | 114133303012442202043 |
6 | 1142402453101405515 |
7 | 36412451601322331 |
oct | 3562601137155667 |
9 | 564842864670362 |
10 | 131031021444023 |
11 | 38828a426a7168 |
12 | 12842833b6989b |
13 | 581623172075c |
14 | 244dd14580451 |
15 | 102363e453bb8 |
hex | 772c097cdbb7 |
131031021444023 has 2 divisors, whose sum is σ = 131031021444024. Its totient is φ = 131031021444022.
The previous prime is 131031021444017. The next prime is 131031021444031. The reversal of 131031021444023 is 320444120130131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131031021444023 - 238 = 130756143537079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131031021440023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515510722011 + 65515510722012.
It is an arithmetic number, because the mean of its divisors is an integer number (65515510722012).
Almost surely, 2131031021444023 is an apocalyptic number.
131031021444023 is a deficient number, since it is larger than the sum of its proper divisors (1).
131031021444023 is an equidigital number, since it uses as much as digits as its factorization.
131031021444023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 131031021444023 its reverse (320444120130131), we get a palindrome (451475141574154).
The spelling of 131031021444023 in words is "one hundred thirty-one trillion, thirty-one billion, twenty-one million, four hundred forty-four thousand, twenty-three".
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