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13103110303 = 69118962533
BaseRepresentation
bin11000011010000000…
…11001100010011111
31020211011210222012121
430031000121202133
5203313344012203
610004113043411
7642464412523
oct141500314237
936734728177
1013103110303
115614400788
122658256567
13130a86410a
148c4329d83
1551a51d0bd
hex30d01989f

13103110303 has 4 divisors (see below), whose sum is σ = 13122073528. Its totient is φ = 13084147080.

The previous prime is 13103110301. The next prime is 13103110367. The reversal of 13103110303 is 30301130131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13103110303 - 21 = 13103110301 is a prime.

It is a super-2 number, since 2×131031103032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13103110301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9480576 + ... + 9481957.

It is an arithmetic number, because the mean of its divisors is an integer number (3280518382).

Almost surely, 213103110303 is an apocalyptic number.

13103110303 is a deficient number, since it is larger than the sum of its proper divisors (18963225).

13103110303 is an equidigital number, since it uses as much as digits as its factorization.

13103110303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18963224.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 13103110303 its reverse (30301130131), we get a palindrome (43404240434).

The spelling of 13103110303 in words is "thirteen billion, one hundred three million, one hundred ten thousand, three hundred three".

Divisors: 1 691 18962533 13103110303