13103112033133 has 4 divisors (see below), whose sum is σ = 13103324507680. Its totient is φ = 13102899558588.

The previous prime is 13103112033103. The next prime is 13103112033157. The reversal of 13103112033133 is 33133021130131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13103112033133 - 2¹³ = 13103112024941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13103112033098 and 13103112033107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13103112033103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106144743 + ... + 106268116.

It is an arithmetic number, because the mean of its divisors is an integer number (3275831126920).

Almost surely, 2^{13103112033133} is an apocalyptic number.

It is an amenable number.

13103112033133 is a deficient number, since it is larger than the sum of its proper divisors (212474547).

13103112033133 is an equidigital number, since it uses as much as digits as its factorization.

13103112033133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 212474546.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 13103112033133 its reverse (33133021130131), we get a palindrome (46236133163264).

The spelling of 13103112033133 in words is "thirteen trillion, one hundred three billion, one hundred twelve million, thirty-three thousand, one hundred thirty-three".