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1310312002011 = 3436770667337
BaseRepresentation
bin10011000100010100101…
…011100111000111011011
311122021010220012102122120
4103010110223213013123
5132432004333031021
62441540553352323
7163444516151235
oct23042453470733
94567126172576
101310312002011
11465777a68a01
12191b44a086a3
139673c62558c
14475c2d27255
152413e3b32c6
hex13114ae71db

1310312002011 has 4 divisors (see below), whose sum is σ = 1747082669352. Its totient is φ = 873541334672.

The previous prime is 1310312002009. The next prime is 1310312002019. The reversal of 1310312002011 is 1102002130131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310312002011 - 21 = 1310312002009 is a prime.

It is a super-2 number, since 2×13103120020112 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1310312002019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218385333666 + ... + 218385333671.

It is an arithmetic number, because the mean of its divisors is an integer number (436770667338).

Almost surely, 21310312002011 is an apocalyptic number.

1310312002011 is a deficient number, since it is larger than the sum of its proper divisors (436770667341).

1310312002011 is an equidigital number, since it uses as much as digits as its factorization.

1310312002011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 436770667340.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 1310312002011 its reverse (1102002130131), we get a palindrome (2412314132142).

The spelling of 1310312002011 in words is "one trillion, three hundred ten billion, three hundred twelve million, two thousand, eleven".

Divisors: 1 3 436770667337 1310312002011