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1310312022113 = 7118455098903
BaseRepresentation
bin10011000100010100101…
…011101100000001100001
311122021010220020110020002
4103010110223230001201
5132432004334201423
62441540554025345
7163444516263653
oct23042453540141
94567126213202
101310312022113
11465777a82016
12191b44a18255
139673c631783
14475c2d306d3
152413e3b9228
hex13114aec061

1310312022113 has 4 divisors (see below), whose sum is σ = 1328767121088. Its totient is φ = 1291856923140.

The previous prime is 1310312022083. The next prime is 1310312022127. The reversal of 1310312022113 is 3112202130131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310312022113 - 214 = 1310312005729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310312027113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9227549381 + ... + 9227549522.

It is an arithmetic number, because the mean of its divisors is an integer number (332191780272).

Almost surely, 21310312022113 is an apocalyptic number.

It is an amenable number.

1310312022113 is a deficient number, since it is larger than the sum of its proper divisors (18455098975).

1310312022113 is an equidigital number, since it uses as much as digits as its factorization.

1310312022113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18455098974.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1310312022113 its reverse (3112202130131), we get a palindrome (4422514152244).

The spelling of 1310312022113 in words is "one trillion, three hundred ten billion, three hundred twelve million, twenty-two thousand, one hundred thirteen".

Divisors: 1 71 18455098903 1310312022113