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13103120243324 = 224801721194621
BaseRepresentation
bin1011111010101100111011…
…0100111101101001111100
31201101122102222102122200202
42332223032310331221330
53204140142240241244
643511253525143032
72521445351246246
oct276531664755174
951348388378622
1013103120243324
1141a2002863891
12157758055aa78
13740807a5cc87
143342a162d096
1517ac977b804e
hexbeaced3da7c

13103120243324 has 24 divisors (see below), whose sum is σ = 22938659624496. Its totient is φ = 6549217920000.

The previous prime is 13103120243249. The next prime is 13103120243371. The reversal of 13103120243324 is 42334202130131.

It is a super-3 number, since 3×131031202433243 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 138432734 + ... + 138527354.

It is an arithmetic number, because the mean of its divisors is an integer number (955777484354).

Almost surely, 213103120243324 is an apocalyptic number.

It is an amenable number.

13103120243324 is a deficient number, since it is larger than the sum of its proper divisors (9835539381172).

13103120243324 is a wasteful number, since it uses less digits than its factorization.

13103120243324 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106637 (or 106635 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 13103120243324 its reverse (42334202130131), we get a palindrome (55437322373455).

The spelling of 13103120243324 in words is "thirteen trillion, one hundred three billion, one hundred twenty million, two hundred forty-three thousand, three hundred twenty-four".

Divisors: 1 2 4 4801 7211 9602 14422 19204 28844 94621 189242 378484 34620011 69240022 138480044 454275421 682312031 908550842 1364624062 1817101684 2729248124 3275780060831 6551560121662 13103120243324