Base | Representation |
---|---|
bin | 1011111010101100111011… |
… | …0111111110000010000101 |
3 | 1201101122110000220200121002 |
4 | 2332223032313332002011 |
5 | 3204140142441000201 |
6 | 43511253554103045 |
7 | 2521445361040460 |
oct | 276531667760205 |
9 | 51348400820532 |
10 | 13103121031301 |
11 | 41a2003251904 |
12 | 157758087aa85 |
13 | 740807c77832 |
14 | 3342a17962d7 |
15 | 17ac978c176b |
hex | beacedfe085 |
13103121031301 has 4 divisors (see below), whose sum is σ = 14974995464352. Its totient is φ = 11231246598252.
The previous prime is 13103121031279. The next prime is 13103121031303. The reversal of 13103121031301 is 10313012130131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13103121031301 - 230 = 13102047289477 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13103121031303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 935937216515 + ... + 935937216528.
It is an arithmetic number, because the mean of its divisors is an integer number (3743748866088).
Almost surely, 213103121031301 is an apocalyptic number.
It is an amenable number.
13103121031301 is a deficient number, since it is larger than the sum of its proper divisors (1871874433051).
13103121031301 is an equidigital number, since it uses as much as digits as its factorization.
13103121031301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1871874433050.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 13103121031301 its reverse (10313012130131), we get a palindrome (23416133161432).
The spelling of 13103121031301 in words is "thirteen trillion, one hundred three billion, one hundred twenty-one million, thirty-one thousand, three hundred one".
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