Base | Representation |
---|---|
bin | 11101110010110001000101… |
… | …000000111100101110101111 |
3 | 122011221112112202222111212221 |
4 | 131302301011000330232233 |
5 | 114133312034124034043 |
6 | 1142403140135140211 |
7 | 36412515416164246 |
oct | 3562610500745657 |
9 | 564845482874787 |
10 | 131032020143023 |
11 | 3882940541153a |
12 | 12842a72514667 |
13 | 58163605c36cc |
14 | 244ddab06d95d |
15 | 102369be798ed |
hex | 772c4503cbaf |
131032020143023 has 2 divisors, whose sum is σ = 131032020143024. Its totient is φ = 131032020143022.
The previous prime is 131032020143009. The next prime is 131032020143041. The reversal of 131032020143023 is 320341020230131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131032020143023 - 217 = 131032020011951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131032020143083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65516010071511 + 65516010071512.
It is an arithmetic number, because the mean of its divisors is an integer number (65516010071512).
Almost surely, 2131032020143023 is an apocalyptic number.
131032020143023 is a deficient number, since it is larger than the sum of its proper divisors (1).
131032020143023 is an equidigital number, since it uses as much as digits as its factorization.
131032020143023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 131032020143023 its reverse (320341020230131), we get a palindrome (451373040373154).
The spelling of 131032020143023 in words is "one hundred thirty-one trillion, thirty-two billion, twenty million, one hundred forty-three thousand, twenty-three".
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