13103203113131 has 4 divisors (see below), whose sum is σ = 13103230268352. Its totient is φ = 13103175957912.

The previous prime is 13103203113113. The next prime is 13103203113151. The reversal of 13103203113131 is 13131130230131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13103203113131 - 2²⁶ = 13103136004267 is a prime.

It is a super-2 number, since 2×13103203113131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13103203113097 and 13103203113106.

It is not an unprimeable number, because it can be changed into a prime (13103203113151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12840476 + ... + 13823321.

It is an arithmetic number, because the mean of its divisors is an integer number (3275807567088).

Almost surely, 2^{13103203113131} is an apocalyptic number.

13103203113131 is a deficient number, since it is larger than the sum of its proper divisors (27155221).

13103203113131 is an equidigital number, since it uses as much as digits as its factorization.

13103203113131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27155220.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 13103203113131 its reverse (13131130230131), we get a palindrome (26234333343262).

The spelling of 13103203113131 in words is "thirteen trillion, one hundred three billion, two hundred three million, one hundred thirteen thousand, one hundred thirty-one".