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131032031132293 is a prime number
BaseRepresentation
bin11101110010110001000101…
…101010110111101010000101
3122011221112120112122211022221
4131302301011222313222011
5114133312044432213133
61142403141210452341
736412515611454034
oct3562610552675205
9564845515584287
10131032031132293
1138829410637985
1212842a761340b1
135816362970635
14244ddac6d071b
15102369cdeaa2d
hex772c45ab7a85

131032031132293 has 2 divisors, whose sum is σ = 131032031132294. Its totient is φ = 131032031132292.

The previous prime is 131032031132273. The next prime is 131032031132339. The reversal of 131032031132293 is 392231130230131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74004417066724 + 57027614065569 = 8602582^2 + 7551663^2 .

It is a cyclic number.

It is not a de Polignac number, because 131032031132293 - 237 = 130894592178821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131032031132203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65516015566146 + 65516015566147.

It is an arithmetic number, because the mean of its divisors is an integer number (65516015566147).

Almost surely, 2131032031132293 is an apocalyptic number.

It is an amenable number.

131032031132293 is a deficient number, since it is larger than the sum of its proper divisors (1).

131032031132293 is an equidigital number, since it uses as much as digits as its factorization.

131032031132293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 34.

The spelling of 131032031132293 in words is "one hundred thirty-one trillion, thirty-two billion, thirty-one million, one hundred thirty-two thousand, two hundred ninety-three".