Base | Representation |
---|---|
bin | 11101110010110001000101… |
… | …101010110111101100010101 |
3 | 122011221112120112122211112021 |
4 | 131302301011222313230111 |
5 | 114133312044432214222 |
6 | 1142403141210453141 |
7 | 36412515611454331 |
oct | 3562610552675425 |
9 | 564845515584467 |
10 | 131032031132437 |
11 | 38829410637aa6 |
12 | 12842a761341b1 |
13 | 5816362970716 |
14 | 244ddac6d07c1 |
15 | 102369cdeaac7 |
hex | 772c45ab7b15 |
131032031132437 has 2 divisors, whose sum is σ = 131032031132438. Its totient is φ = 131032031132436.
The previous prime is 131032031132399. The next prime is 131032031132533. The reversal of 131032031132437 is 734231130230131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80643740594596 + 50388290537841 = 8980186^2 + 7098471^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131032031132437 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131032031232437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65516015566218 + 65516015566219.
It is an arithmetic number, because the mean of its divisors is an integer number (65516015566219).
Almost surely, 2131032031132437 is an apocalyptic number.
It is an amenable number.
131032031132437 is a deficient number, since it is larger than the sum of its proper divisors (1).
131032031132437 is an equidigital number, since it uses as much as digits as its factorization.
131032031132437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27216, while the sum is 34.
Adding to 131032031132437 its reverse (734231130230131), we get a palindrome (865263161362568).
The spelling of 131032031132437 in words is "one hundred thirty-one trillion, thirty-two billion, thirty-one million, one hundred thirty-two thousand, four hundred thirty-seven".
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