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131032031400157 is a prime number
BaseRepresentation
bin11101110010110001000101…
…101011111001000011011101
3122011221112120120011102202211
4131302301011223321003131
5114133312100014301112
61142403141220320421
736412515613651006
oct3562610553710335
9564845516142684
10131032031400157
1138829410800158
1212842a76243111
135816362a35534
14244ddac7601ad
15102369ce500a7
hex772c45af90dd

131032031400157 has 2 divisors, whose sum is σ = 131032031400158. Its totient is φ = 131032031400156.

The previous prime is 131032031400131. The next prime is 131032031400169. The reversal of 131032031400157 is 751004130230131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117115445916121 + 13916585484036 = 10821989^2 + 3730494^2 .

It is an emirp because it is prime and its reverse (751004130230131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131032031400157 - 211 = 131032031398109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131032031440157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65516015700078 + 65516015700079.

It is an arithmetic number, because the mean of its divisors is an integer number (65516015700079).

Almost surely, 2131032031400157 is an apocalyptic number.

It is an amenable number.

131032031400157 is a deficient number, since it is larger than the sum of its proper divisors (1).

131032031400157 is an equidigital number, since it uses as much as digits as its factorization.

131032031400157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7560, while the sum is 31.

Adding to 131032031400157 its reverse (751004130230131), we get a palindrome (882036161630288).

The spelling of 131032031400157 in words is "one hundred thirty-one trillion, thirty-two billion, thirty-one million, four hundred thousand, one hundred fifty-seven".