131032032141301 has 4 divisors (see below), whose sum is σ = 137928454885600. Its totient is φ = 124135609397004.

The previous prime is 131032032141281. The next prime is 131032032141317. The reversal of 131032032141301 is 103141230230131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131032032141301 - 2¹³ = 131032032133109 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131032032141331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3448211372121 + ... + 3448211372158.

It is an arithmetic number, because the mean of its divisors is an integer number (34482113721400).

Almost surely, 2^{131032032141301} is an apocalyptic number.

It is an amenable number.

131032032141301 is a deficient number, since it is larger than the sum of its proper divisors (6896422744299).

131032032141301 is an equidigital number, since it uses as much as digits as its factorization.

131032032141301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6896422744298.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 131032032141301 its reverse (103141230230131), we get a palindrome (234173262371432).

The spelling of 131032032141301 in words is "one hundred thirty-one trillion, thirty-two billion, thirty-two million, one hundred forty-one thousand, three hundred one".