131032311301 has 4 divisors (see below), whose sum is σ = 131900075104. Its totient is φ = 130164547500.

The previous prime is 131032311287. The next prime is 131032311433. The reversal of 131032311301 is 103113230131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131032311301 - 2²⁵ = 130998756869 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131032311001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 433881675 + ... + 433881976.

It is an arithmetic number, because the mean of its divisors is an integer number (32975018776).

Almost surely, 2^131032311301 is an apocalyptic number.

It is an amenable number.

131032311301 is a deficient number, since it is larger than the sum of its proper divisors (867763803).

131032311301 is an equidigital number, since it uses as much as digits as its factorization.

131032311301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 867763802.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 131032311301 its reverse (103113230131), we get a palindrome (234145541432).

The spelling of 131032311301 in words is "one hundred thirty-one billion, thirty-two million, three hundred eleven thousand, three hundred one".